D^2(D^2+4)=x^2

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Solution for D^2(D^2+4)=x^2 equation: 



^2(^2+4)=D^2

We move all terms to the left:

^2(^2+4)-(D^2)=0

We add all the numbers together, and all the variables

-1D^2=0

a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$D=\frac{-b}{2a}=\frac{0}{-2}=0$

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